Push Operation
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Pop Operation
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Stack Data Structure

c++

C

CPP

#include<iostream>
#include<conio.h>
#include<string.h>
 using namespace std;
  int BinToDec(char bin[])
    {
     int dec=0,base=1,temp,len,i=0;
      for(i=strlen(bin)-1;i>=0;i--)
       {
        temp=int(bin[i])-48;
         dec=temp*base+dec;
        base*=2; 
    }
     return dec;
 }
   int main()
    {
     char bin[7];
     cout<<"Enter a binary No.:-";
     cin>>bin;
     int bn=BinToDec(bin);
     cout<<"Decimal No.="<<bn;
     getch();
    }

#include<stdio.h>
#include<string.h>
   /* char* Delete(char str[],int p)
  {
    	int i;
    	for(i=p-1;i<strlen(str);i++)
  	   	 str[i]=str[i+1];
		return str;
	}*/
	void Delete(char str[],int p)
     {
    	int i;
    	for(i=p-1;i<strlen(str);i++)
  	   	 str[i]=str[i+1];
	}
 int main()
  {
  	char str[100],*str1,ch;
	int i,j,length;
  	printf("Enter a string:-");
  	scanf("%s",str);
  	printf("Enter the character you want to delete a character:-");
  	fflush(stdin);
    scanf("%c",&ch);
    printf("Before deletion  = %s\n",str);
    length=strlen(str);
    for(i=0;i<length;i++)
       {
       	  if(str[i]==ch)
       	     {
       	     	for(j=i;j<length;j++)
  	   	        str[j]=str[j+1];
       	     	break;
			 }
	   }
	if(i==length)
	    printf("given character is not present.");
    else
        printf("After deletion  = %s\n",str);
    return 0;
  }

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HexaDecimal No. Decimal No.

#include<iostream>
#include<string.h>
#include<iomanip>
 using namespace std;
  int HexaToDec(char *ch)
 {
     int i,base=1,temp,dec=0;
     i=strlen(ch)-1;
         while(i>=0)
         {
             if(ch[i]>='A'&&ch[i]<='F')
              temp=int(ch[i])-55;
              else
               temp=int(ch[i])-48;
            dec+=temp*base;
            base*=16;
            i--;
         }
       return (dec);
 }
 int main()
  {
    char ch[3]="1A";
    cout<<"Enter a Hexadecimal number:-";
    char hexa[100];
    cin>>hexa;
 cout<<endl<<HexaToDec(hexa);
   return 0;
  }

Mathematical Calculation

Enter 1st No.:-

Calculator

This is My Calculator

1. The preprocessor of a computer can understand only View Answer machine language   instructions.
2. View Answer High Level Language can be translated into machine code by compiler.
3. View Answer COBOL is the business oriented language.
4. We you View Answer braces ({,}) symbol at the beginning and end of a C program.
5. Two section of a program are connected by View Answer connector .